Reynoldsville (Pennsylvania)
| Articul per Ladin Gherdëina | 
|
Reynoldsville ie na zità te la Pennsylvania te i Stac Unii d’America. Tl 2019 ovela na populazion de 2 659 sun na spersa de 3,6 km².[2] Reynoldsville fej pert de la contea Jefferson.
| Reynoldsville | |
|---|---|
 | |
| Nfurmazions prinzipeles | |
| Stat |  Stac Unii
|
| Stat federel |  Pennsylvania
|
| County | Jefferson |
| Populazion | 2 549 ab. (1 auril 2020)[1] |
| Densità | 1 710,7 ab./km² |
| Geografia | |
| Coordinedes | 41°6′N 78°53′W / 41.100°N 78.883°W |
| Autëza | 1 391 m |
| Spersa | 1,5 km² |
| Auter | |
| Zona d'orar | UTC-05:00 (ET) UTC-04:00 (d'instà) |
| Codesc FIPS | 42-64376 |
| Cherta | |
  Reynoldsville Reynoldsville (Stac Unii d'America) | |
Geografia
mudéStoria
mudéNotes
mudé- ↑ 1,0 1,1 1,2 https://data.census.gov/cedsci/table?t=Populations%20and%20People&g=0100000US,%241600000&y=2020.
- ↑ "QuickFacts". U.S. Census Bureau. April 1, 2020. Archivià dal uriginel ai February 5, 2021. Trat ite ai May 3, 2022.