Summerville (Georgia (stat American))
| Articul per Ladin Gherdëina | 
|
Summerville ie na zità te la Georgia te i Stac Unii d’America. Tl 2019 ovela na populazion de 4 283 sun na spersa de 10,4 km².[2] Summerville fej pert de la contea Chattooga.
| Summerville | |
|---|---|
 | |
| Nfurmazions prinzipeles | |
| Stat |  Stac Unii
|
| Stat federel |  Georgia (stat American)
|
| County | Chattooga |
| Populazion | 4 435 ab. (1 auril 2020)[1] |
| Densità | 426,6 ab./km² |
| Geografia | |
| Coordinedes | 34°29′N 85°21′W / 34.483°N 85.350°W |
| Autëza | 198 m |
| Spersa | 10,4 km² |
| Auter | |
| Zona d'orar | UTC-05:00 (ET) UTC-04:00 (d'instà) |
| Codesc de la posta | 30747 |
| Codesc FIPS | 13-74376 |
| Plata internet | www |
| Cherta | |
  Summerville Summerville (Stac Unii d'America) | |
Geografia
mudéStoria
mudéNotes
mudé- ↑ 1,0 1,1 1,2 https://data.census.gov/cedsci/table?t=Populations%20and%20People&g=0100000US,%241600000&y=2020.
- ↑ "QuickFacts". U.S. Census Bureau. April 1, 2020. Archivià dal uriginel ai February 5, 2021. Trat ite ai May 3, 2022.